Module 5 · Dispersion, Shape, and Robust Statistics Lesson 48 of 120
Z-Score, Robust Z-Score, and Standardization
Standardizing alerts without turning unusual into fraudulent.
Transcript
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Does a robust z-score of 4.72 prove the transaction is fraudulent?
Code lab
Run it yourself
The lesson source in 7 languages. Edit it, run TypeScript and Python right here, and compare with the expected output.
/**
* Fintech Math Bootcamp · Lesson 048 of 120
* Z-Score, Robust Z-Score, and Standardization
* Module 05: Dispersion, Shape, and Robust Statistics
*
* Scenario: Standardizing alerts without turning unusual into fraudulent
* Rule: z = (x−mean)/s; robust z = 0.67448975(x−median)/MAD
*
* Try it: Does a robust z-score of 4.72 prove the transaction is fraudulent?
*
* Lesson article: https://thefintechbuilder.com/financial-mathematics-statistics-and-data-foundations/dispersion-shape-and-robust-statistics/z-score-robust-z-score-and-standardization/
* Free course: https://courses.thefintechbuilder.com
* Synthetic teaching example, not financial advice or a production library.
*/
export function lesson048() {
const observed = 9, mean = 3.6, sd = Math.sqrt(10.3);
const median = 2, rawMAD: number = 1;
const result = {z:(observed-mean)/sd,
robustZ: rawMAD===0 ? null : .67448975*(observed-median)/rawMAD};
return result;
}
export const checkedResult = {"z":1.6825777726943407,"robustZ":4.72142825};
// Run this file directly: npx tsx lessons/05-dispersion-shape-and-robust-statistics/048-z-score-robust-z-score-and-standardization.ts
if (process.argv[1] && import.meta.url.endsWith(process.argv[1].replace(/\\/g, "/").split("/").pop()!)) {
console.log(JSON.stringify(lesson048(), null, 2));
}
Your output
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Expected output
{
"z": 1.6825777726943407,
"robustZ": 4.72142825
}# Fintech Math Bootcamp · Lesson 048 of 120
# Z-Score, Robust Z-Score, and Standardization
# Module 05: Dispersion, Shape, and Robust Statistics
#
# Scenario: Standardizing alerts without turning unusual into fraudulent
# Rule: z = (x−mean)/s; robust z = 0.67448975(x−median)/MAD
#
# Try it: Does a robust z-score of 4.72 prove the transaction is fraudulent?
#
# Lesson article: https://thefintechbuilder.com/financial-mathematics-statistics-and-data-foundations/dispersion-shape-and-robust-statistics/z-score-robust-z-score-and-standardization/
# Free course: https://courses.thefintechbuilder.com
# Synthetic teaching example, not financial advice or a production library.
import json
import math
def lesson048() -> dict:
observed, mean, sd = 9, 3.6, math.sqrt(10.3)
median, raw_mad = 2, 1
return {
"z": (observed - mean) / sd,
# A zero MAD has no robust scale, so the robust score is undefined (null).
"robustZ": None if raw_mad == 0 else 0.67448975 * (observed - median) / raw_mad,
}
if __name__ == "__main__":
print(json.dumps(lesson048(), indent=2))
Your output
Press Run to execute the code in your browser.
Expected output
{
"z": 1.6825777726943407,
"robustZ": 4.72142825
}/**
* Fintech Math Bootcamp · Lesson 048 of 120
* Z-Score, Robust Z-Score, and Standardization
* Module 05: Dispersion, Shape, and Robust Statistics
*
* Scenario: Standardizing alerts without turning unusual into fraudulent
* Rule: z = (x−mean)/s; robust z = 0.67448975(x−median)/MAD
*
* Try it: Does a robust z-score of 4.72 prove the transaction is fraudulent?
*
* Lesson article: https://thefintechbuilder.com/financial-mathematics-statistics-and-data-foundations/dispersion-shape-and-robust-statistics/z-score-robust-z-score-and-standardization/
* Free course: https://courses.thefintechbuilder.com
* Synthetic teaching example, not financial advice or a production library.
*/
import java.util.ArrayList;
import java.util.LinkedHashMap;
import java.util.List;
import java.util.Map;
public class Main {
static Map<String, Object> lesson048() {
double observed = 9, mean = 3.6, sd = Math.sqrt(10.3);
double median = 2, rawMAD = 1;
Map<String, Object> result = new LinkedHashMap<String, Object>();
result.put("z", (observed - mean) / sd);
// A zero MAD has no robust scale, so the robust score is undefined (null).
result.put("robustZ", rawMAD == 0 ? null : (Double) (0.67448975 * (observed - median) / rawMAD));
return result;
}
public static void main(String[] args) {
System.out.println(toJson(lesson048(), ""));
}
// --- Minimal JSON printer: maps keep insertion order, 2-space indent. ---
static String toJson(Object value, String indent) {
if (value == null) return "null";
if (value instanceof String) return "\"" + value + "\"";
if (value instanceof Double) return formatNumber((Double) value);
if (value instanceof Number) return value.toString();
if (value instanceof double[]) {
List<Object> items = new ArrayList<Object>();
for (double v : (double[]) value) items.add(v);
return toJson(items, indent);
}
String inner = indent + " ";
StringBuilder sb = new StringBuilder();
if (value instanceof Map) {
Map<?, ?> map = (Map<?, ?>) value;
if (map.isEmpty()) return "{}";
sb.append("{\n");
int i = 0;
for (Map.Entry<?, ?> entry : map.entrySet()) {
sb.append(inner).append('"').append(entry.getKey()).append("\": ")
.append(toJson(entry.getValue(), inner))
.append(++i < map.size() ? ",\n" : "\n");
}
return sb.append(indent).append('}').toString();
}
List<?> list = (List<?>) value;
if (list.isEmpty()) return "[]";
sb.append("[\n");
for (int i = 0; i < list.size(); i++) {
sb.append(inner).append(toJson(list.get(i), inner))
.append(i + 1 < list.size() ? ",\n" : "\n");
}
return sb.append(indent).append(']').toString();
}
static String formatNumber(double v) {
if (Double.isNaN(v) || Double.isInfinite(v)) return "null";
if (v == Math.rint(v) && Math.abs(v) < 1e15) return Long.toString((long) v);
return Double.toString(v);
}
}
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Read the code here, then run it in your own toolchain or a ready-made cloud workspace.
Expected output
{
"z": 1.6825777726943407,
"robustZ": 4.72142825
}// Fintech Math Bootcamp · Lesson 048 of 120
// Z-Score, Robust Z-Score, and Standardization
// Module 05: Dispersion, Shape, and Robust Statistics
//
// Scenario: Standardizing alerts without turning unusual into fraudulent
// Rule: z = (x−mean)/s; robust z = 0.67448975(x−median)/MAD
//
// Try it: Does a robust z-score of 4.72 prove the transaction is fraudulent?
//
// Lesson article: https://thefintechbuilder.com/financial-mathematics-statistics-and-data-foundations/dispersion-shape-and-robust-statistics/z-score-robust-z-score-and-standardization/
// Free course: https://courses.thefintechbuilder.com
// Synthetic teaching example, not financial advice or a production library.
package main
import (
"encoding/json"
"fmt"
"math"
)
// Scores holds the classical z-score and the median/MAD robust z-score.
// RobustZ is a pointer so an undefined score prints as null.
type Scores struct {
Z float64 `json:"z"`
RobustZ *float64 `json:"robustZ"`
}
func lesson048() Scores {
observed, mean, sd := 9.0, 3.6, math.Sqrt(10.3)
median, rawMAD := 2.0, 1.0
result := Scores{Z: (observed - mean) / sd}
if rawMAD != 0 {
robustZ := 0.67448975 * (observed - median) / rawMAD
result.RobustZ = &robustZ
}
return result
}
func main() {
out, _ := json.MarshalIndent(lesson048(), "", " ")
fmt.Println(string(out))
}
No browser runner for Go yet
Read the code here, then run it in your own toolchain or a ready-made cloud workspace.
Expected output
{
"z": 1.6825777726943407,
"robustZ": 4.72142825
}/**
* Fintech Math Bootcamp · Lesson 048 of 120
* Z-Score, Robust Z-Score, and Standardization
* Module 05: Dispersion, Shape, and Robust Statistics
*
* Scenario: Standardizing alerts without turning unusual into fraudulent
* Rule: z = (x−mean)/s; robust z = 0.67448975(x−median)/MAD
*
* Try it: Does a robust z-score of 4.72 prove the transaction is fraudulent?
*
* Lesson article: https://thefintechbuilder.com/financial-mathematics-statistics-and-data-foundations/dispersion-shape-and-robust-statistics/z-score-robust-z-score-and-standardization/
* Free course: https://courses.thefintechbuilder.com
* Synthetic teaching example, not financial advice or a production library.
*/
#include <charconv>
#include <cmath>
#include <iostream>
#include <optional>
#include <string>
#include <utility>
#include <vector>
// --- Minimal JSON value and printer: objects keep insertion order, 2-space indent. ---
struct Json {
enum class Kind { Null, Number, Text, Array, Object };
Kind kind = Kind::Null;
double number = 0;
std::string text;
std::vector<std::string> keys; // object keys, parallel to items
std::vector<Json> items; // array elements or object values
};
Json num(double v) { Json j; j.kind = Json::Kind::Number; j.number = v; return j; }
Json str(const std::string& s) { Json j; j.kind = Json::Kind::Text; j.text = s; return j; }
Json arr(const std::vector<Json>& values) { Json j; j.kind = Json::Kind::Array; j.items = values; return j; }
Json arr(const std::vector<double>& values) {
std::vector<Json> items;
for (double v : values) items.push_back(num(v));
return arr(items);
}
Json obj(const std::vector<std::pair<std::string, Json>>& fields) {
Json j;
j.kind = Json::Kind::Object;
for (const auto& [key, value] : fields) { j.keys.push_back(key); j.items.push_back(value); }
return j;
}
std::string formatNumber(double v) {
if (!std::isfinite(v)) return "null";
char buf[64];
auto end = std::to_chars(buf, buf + sizeof buf, v).ptr; // shortest round-trip form
return std::string(buf, end);
}
void writeJson(std::ostream& out, const Json& j, const std::string& indent) {
switch (j.kind) {
case Json::Kind::Null: out << "null"; return;
case Json::Kind::Number: out << formatNumber(j.number); return;
case Json::Kind::Text: out << '"' << j.text << '"'; return;
default: break;
}
bool isObject = j.kind == Json::Kind::Object;
if (j.items.empty()) { out << (isObject ? "{}" : "[]"); return; }
std::string inner = indent + " ";
out << (isObject ? "{\n" : "[\n");
for (size_t i = 0; i < j.items.size(); ++i) {
out << inner;
if (isObject) out << '"' << j.keys[i] << "\": ";
writeJson(out, j.items[i], inner);
out << (i + 1 < j.items.size() ? ",\n" : "\n");
}
out << indent << (isObject ? '}' : ']');
}
// --- Lesson ---
Json lesson048() {
const double observed = 9, mean = 3.6, sd = std::sqrt(10.3);
const double median = 2, rawMAD = 1;
// A zero MAD has no robust scale, so the robust score is undefined (null).
std::optional<double> robustZ;
if (rawMAD != 0) robustZ = 0.67448975 * (observed - median) / rawMAD;
return obj({
{"z", num((observed - mean) / sd)},
{"robustZ", robustZ ? num(*robustZ) : Json{}},
});
}
int main() {
writeJson(std::cout, lesson048(), "");
std::cout << '\n';
}
No browser runner for C++ yet
Read the code here, then run it in your own toolchain or a ready-made cloud workspace.
Expected output
{
"z": 1.6825777726943407,
"robustZ": 4.72142825
}// Fintech Math Bootcamp · Lesson 048 of 120
// Z-Score, Robust Z-Score, and Standardization
// Module 05: Dispersion, Shape, and Robust Statistics
//
// Scenario: Standardizing alerts without turning unusual into fraudulent
// Rule: z = (x−mean)/s; robust z = 0.67448975(x−median)/MAD
//
// Try it: Does a robust z-score of 4.72 prove the transaction is fraudulent?
//
// Lesson article: https://thefintechbuilder.com/financial-mathematics-statistics-and-data-foundations/dispersion-shape-and-robust-statistics/z-score-robust-z-score-and-standardization/
// Free course: https://courses.thefintechbuilder.com
// Synthetic teaching example, not financial advice or a production library.
// --- Minimal JSON value and printer: objects keep insertion order, 2-space indent. ---
#[allow(dead_code)]
enum Json {
Null,
Num(f64),
Str(String),
Arr(Vec<Json>),
Obj(Vec<(String, Json)>),
}
#[allow(dead_code)]
fn nums(values: &[f64]) -> Json {
Json::Arr(values.iter().map(|&v| Json::Num(v)).collect())
}
#[allow(dead_code)]
fn obj(fields: Vec<(&str, Json)>) -> Json {
Json::Obj(fields.into_iter().map(|(k, v)| (k.to_string(), v)).collect())
}
fn format_number(v: f64) -> String {
if !v.is_finite() {
return "null".to_string();
}
if v.fract() == 0.0 && v.abs() < 1e15 {
return format!("{}", v as i64);
}
format!("{:?}", v) // shortest round-trip form
}
impl Json {
fn render(&self, indent: &str) -> String {
let inner = format!("{} ", indent);
match self {
Json::Null => "null".to_string(),
Json::Num(v) => format_number(*v),
Json::Str(s) => format!("\"{}\"", s),
Json::Arr(items) if items.is_empty() => "[]".to_string(),
Json::Obj(fields) if fields.is_empty() => "{}".to_string(),
Json::Arr(items) => {
let lines: Vec<String> = items.iter().map(|v| format!("{}{}", inner, v.render(&inner))).collect();
format!("[\n{}\n{}]", lines.join(",\n"), indent)
}
Json::Obj(fields) => {
let lines: Vec<String> = fields
.iter()
.map(|(k, v)| format!("{}\"{}\": {}", inner, k, v.render(&inner)))
.collect();
format!("{{\n{}\n{}}}", lines.join(",\n"), indent)
}
}
}
}
// --- Lesson ---
fn lesson048() -> Json {
let (observed, mean, sd) = (9.0, 3.6, 10.3_f64.sqrt());
let (median, raw_mad): (f64, f64) = (2.0, 1.0);
// A zero MAD has no robust scale, so the robust score is undefined (null).
let robust_z = if raw_mad == 0.0 {
Json::Null
} else {
Json::Num(0.67448975 * (observed - median) / raw_mad)
};
obj(vec![("z", Json::Num((observed - mean) / sd)), ("robustZ", robust_z)])
}
fn main() {
println!("{}", lesson048().render(""));
}
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Read the code here, then run it in your own toolchain or a ready-made cloud workspace.
Expected output
{
"z": 1.6825777726943407,
"robustZ": 4.72142825
}/**
* Fintech Math Bootcamp · Lesson 048 of 120
* Z-Score, Robust Z-Score, and Standardization
* Module 05: Dispersion, Shape, and Robust Statistics
*
* Scenario: Standardizing alerts without turning unusual into fraudulent
* Rule: z = (x−mean)/s; robust z = 0.67448975(x−median)/MAD
*
* Try it: Does a robust z-score of 4.72 prove the transaction is fraudulent?
*
* Lesson article: https://thefintechbuilder.com/financial-mathematics-statistics-and-data-foundations/dispersion-shape-and-robust-statistics/z-score-robust-z-score-and-standardization/
* Free course: https://courses.thefintechbuilder.com
* Synthetic teaching example, not financial advice or a production library.
*/
using System;
using System.Text.Json;
var options = new JsonSerializerOptions { WriteIndented = true };
Console.WriteLine(JsonSerializer.Serialize(Lesson048(), options));
static object Lesson048()
{
double observed = 9, mean = 3.6, sd = Math.Sqrt(10.3);
double median = 2, rawMad = 1;
// A zero MAD has no robust scale, so the robust score is undefined (null).
double? robustZ = rawMad == 0 ? null : 0.67448975 * (observed - median) / rawMad;
return new { z = (observed - mean) / sd, robustZ };
}
No browser runner for C# yet
Read the code here, then run it in your own toolchain or a ready-made cloud workspace.
Expected output
{
"z": 1.6825777726943407,
"robustZ": 4.72142825
}Prefer your own machine? Every file is in the course repository · open it in Codespaces.
Lesson notes
The rule
z = (x−mean)/s; robust z = 0.67448975(x−median)/MAD